[Ri...] Posted June 21, 2022 Share Posted June 21, 2022 (All numbers are metric) I have a part that is bowed 2.31, it is 1080 long, but measures 1079.54897. The bow happens to be almost symmetric. How do I calculate the linear loss? Link to comment Share on other sites More sharing options...
[Cl...] Posted June 21, 2022 Share Posted June 21, 2022 Sounds like you need the chord length. sin(Angle A/2)*2*Radius. Link to comment Share on other sites More sharing options...
[Ma...] Posted June 21, 2022 Share Posted June 21, 2022 This can be problematic - for calculation you need more then just these two numbers. As Clarke wrote - you need R and angle. All i found was trials - each repetition you are comming closer to result. SolidWorks denies to work ( radius will be very big ). Found Hugens derived formula ( don't know if it helps ): Link to comment Share on other sites More sharing options...
[Ri...] Posted June 21, 2022 Author Share Posted June 21, 2022 Well we know M = 1079.54897 (Actual measured value) C-D = 2.31460 (Actual measured value assumed from "Form") I think I need to calculate "m". I wasn't able to create a reliable circle in Calypso, I attempted with the same data 4 times, it resulted in four different diameters. Link to comment Share on other sites More sharing options...
[Er...] Posted June 21, 2022 Share Posted June 21, 2022 Maybe try using the chord/height Ratio calculate the Length be linear interpolation? This is found in the machinery handbook. You find it by searching chord length. Based on numbers you posted, your ratio is .002139 which you can used to calculate your length. Link to comment Share on other sites More sharing options...
[Ma...] Posted June 21, 2022 Share Posted June 21, 2022 Please sign in to view this quote. "m" is simple trigonometry - pythagoras: m^2=d^2+a^2 m^2=(M/2)^2+(C-D)^2 m^2=539,774485^2 + 2,31460^2 m^2=291 356,494657015225 + 5,35737316 m^2=291 361,852030175225 m=539,7794475803753914171952577488 Link to comment Share on other sites More sharing options...
[Ri...] Posted June 21, 2022 Author Share Posted June 21, 2022 Please sign in to view this quote. I'd thank you like 5 times but the forum wont let me. 😉 Link to comment Share on other sites More sharing options...
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