Jump to content

I could use some math help.


---
 Share

Recommended Posts

(All numbers are metric)
I have a part that is bowed 2.31, it is 1080 long, but measures 1079.54897.
The bow happens to be almost symmetric.
How do I calculate the linear loss?
Link to comment
Share on other sites

This can be problematic - for calculation you need more then just these two numbers. As Clarke wrote - you need R and angle.
All i found was trials - each repetition you are comming closer to result.

SolidWorks denies to work ( radius will be very big ).

Found Hugens derived formula ( don't know if it helps ): 3001_ec9c633a9915f87288ac62b5086c0854.png
3001_bbb6c8a69269f2988fc0c2c356b8d625.png
Link to comment
Share on other sites

Well we know
M = 1079.54897 (Actual measured value)
C-D = 2.31460 (Actual measured value assumed from "Form")
I think I need to calculate "m".
I wasn't able to create a reliable circle in Calypso, I attempted with the same data 4 times, it resulted in four different diameters.
Link to comment
Share on other sites

Maybe try using the chord/height Ratio calculate the Length be linear interpolation? This is found in the machinery handbook. You find it by searching chord length. Based on numbers you posted, your ratio is .002139 which you can used to calculate your length.
1417_553649ad5a2e4e22de03f00a585b868d.jpg
1417_0301a8e71973af0991d55329c687d297.jpg
Link to comment
Share on other sites

Please sign in to view this quote.

"m" is simple trigonometry - pythagoras:
  • m^2=d^2+a^2
  • m^2=(M/2)^2+(C-D)^2
    m^2=539,774485^2 + 2,31460^2
    m^2=291 356,494657015225 + 5,35737316
    m^2=291 361,852030175225
    m=539,7794475803753914171952577488
Link to comment
Share on other sites

 Share

×
×
  • Create New...