[An...] Posted May 10, 2022 Share Posted May 10, 2022 Hello all If the Coefficient is 23.6 *10^-6/K How do i type 23.6 *10^-6/K in Coefficient? Is just it 0.0000236? Thank you0510-1.JPG0510.JPG Link to comment Share on other sites More sharing options...
[Er...] Posted May 10, 2022 Share Posted May 10, 2022 You just need to type the 23.6. The rest of it will be calculated and in the gray corr. value box, it will show the correction value computed from the temp/coefficient for the measured lengths. Link to comment Share on other sites More sharing options...
[An...] Posted May 11, 2022 Author Share Posted May 11, 2022 Thank you Eric! 1 more question what if i dont know the material name? Link to comment Share on other sites More sharing options...
[To...] Posted May 11, 2022 Share Posted May 11, 2022 Please sign in to view this quote. Let the part reach 68 degrees and don't worry about expansion. Link to comment Share on other sites More sharing options...
[Er...] Posted May 12, 2022 Share Posted May 12, 2022 As Tom mentioned, checking your part in a 68 degree controlled environment would be the best option. If you must use the thermal expansion because you are holding tolerances so tight that it will be affected, you will probably need to have the material tested, to find out what it is, or if you know the type of metal, you can get quite close. Aluminum's coefficient is 21-24, which is a very small deviation between the two. Good luck! Link to comment Share on other sites More sharing options...
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