[Me...] Posted February 20, 2020 Share Posted February 20, 2020 I have a part that has a note that states the "orientation of 3° plane back to slot to be within 5° as shown in the capture below. I believe the number I'm looking for is 90°...I can't seem to get this measurement though. I get the 3° no problem... Link to comment Share on other sites More sharing options...
[Da...] Posted February 20, 2020 Share Posted February 20, 2020 Do you get a A1 and A2 angle on the 3 degree face ? Just spitting out thoughts... Could you create a theo plane and intersect with the 3 degree plane? The resulting line would be parallel with the slot ! Link to comment Share on other sites More sharing options...
[Me...] Posted February 20, 2020 Author Share Posted February 20, 2020 To answer the first question for A1/A2, yes. As far as intersecting the 3 degree plane, I've tried intersecting, theoretical feature projections/intersections...Nothing gives me the orientation back to the slot though. I'm fairly confident it should be 90 degrees. Link to comment Share on other sites More sharing options...
[Jo...] Posted February 20, 2020 Share Posted February 20, 2020 Please sign in to view this quote. So Dave's idea.. If you change A1 A2 to angle instead of vector, one is 3 degrees and the other zero ? If you are leveled to keyway in that alignment, I think that zero is what you are looking for. If the key was rotated those A1 and A2 values would start changing. Link to comment Share on other sites More sharing options...
[Jo...] Posted February 20, 2020 Share Posted February 20, 2020 Maybe use a formula , grab the deviation of A1 or A2 , nominally zero, and build theoretical plane using actuals. You could measure Angle Between Features from Theo plane and Symmetry of slot. Link to comment Share on other sites More sharing options...
[Je...] Posted February 20, 2020 Share Posted February 20, 2020 Here is my .02 Intersect the 3º face (measured as a plane) with the large face on the back side that the angle call out is specified to (also measured as a plane). This will create a line that is nominally parallel to the center line of the slot that should intersect somewhere near your blue arrow. Call the 0º ± 5º from the created intersection to the centerline of the slot. I believe your nominal should be 0º rather than 90º I sometimes have issue with reporting angles between two lines that are nominally parallel and will create a theoretical plane through one line (using a formula to recall angles). This may just be a shortfall in my grasp of the angles being shown so maybe I am the only one in the wide wide web that has a problem there. Link to comment Share on other sites More sharing options...
[Jo...] Posted February 21, 2020 Share Posted February 21, 2020 Please sign in to view this quote. This made my brain hurt. It may be the most elegant solution though. Did you try this ? Link to comment Share on other sites More sharing options...
[Me...] Posted February 21, 2020 Author Share Posted February 21, 2020 Honestly I just swapped the space axis for the A1/A2 and called it a day. Didn't get a chance to mess around because of workload... Link to comment Share on other sites More sharing options...
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