[Ky...] Posted February 18, 2020 Share Posted February 18, 2020 Hey All, I have a part that has been a pain forever. Now I'm trying to check it on CMM. As you can see it is only .438 wide, but it has a R1.938, R1.625, Plus more internal and external Radius. With the part being so small how do I find the location and size of the radius. I have heard about constraints but I have never had any experience using them to get Radius's and locations. Any help would be appreciated. Thanks KyleNew part.png Link to comment Share on other sites More sharing options...
[Jo...] Posted February 18, 2020 Share Posted February 18, 2020 On something like that you can use Radius Measurement. Then filter with Min, Max, or Avg. That will give you radial DISTANCES to the feature from the nominal center. Those will be alignment dependent. As I understand it, treats the center point as pinned in space and gives polar radius. If you apply constraints, you are effectively taking that portion out of the calculation, assuming that constraint is NOT a variable. Either way you need to have the circle feature in an alignment that makes sense. Link to comment Share on other sites More sharing options...
[Ro...] Posted February 18, 2020 Share Posted February 18, 2020 Try touch points instead of scanning. Do a 7 point circle, or try a 3 level cylinder on that surface, all touch points. Link to comment Share on other sites More sharing options...
[Ri...] Posted February 18, 2020 Share Posted February 18, 2020 Create an Alignment from the Datum's Determine the Arc angle (Length of scan) Open the Circle feature, open Evaluation Under Evaluation Constraints select Radius (This allows the calculation of the location only). Set applicable Filters and Outlier conditions. Copy the feature and paste as new (I tend to rename the new feature IE: Circle2 as Circle2.2 for recognition) Open the new feature Under Options select Recall Feature Points Select the feature to recall Open Evaluation Under Evaluation Constraints, deselect Radius and select X, Y Z coordinates (This allows calculation of the Radius) I have had success using this method for many years. Link to comment Share on other sites More sharing options...
[Ky...] Posted February 19, 2020 Author Share Posted February 19, 2020 Thanks all for your all your help. Kyle Link to comment Share on other sites More sharing options...
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