[Me...] Posted January 2, 2020 Share Posted January 2, 2020 Can someone figure out the straight line location to the face rotated at 5° for me on this drawing that I have highlighted? Please and thank you. Link to comment Share on other sites More sharing options...
[Ja...] Posted January 2, 2020 Share Posted January 2, 2020 cos(5) = 2.375/? ? = 2.375/cos(5) = 2.3841 Link to comment Share on other sites More sharing options...
[Ch...] Posted January 2, 2020 Share Posted January 2, 2020 Correct, answer = 2.38407 work = 2.375 / cos(5) Or if you really feel like being lazy then just use any right triangle solver. http://www.cleavebooks.co.uk/scol/calrtri.htm Link to comment Share on other sites More sharing options...
[Br...] Posted January 2, 2020 Share Posted January 2, 2020 Hmm I'm not sure that simple trig formula finds the dimension you are looking for if I understand you correctly. It looks to me to be much more complex than that. If you are trying to get that distance normal to the 5 degree angle where it intersects that center bore at the front plane, there's a lot of other things to consider. First you need to figure out where that point at 2.375 would be at the intersection of the 5 degree angle and the .625 width. Then from there you can figure out the distance normal to the 5 degree angle. So you can start with TAN(5)= x/.625. solve for X to find the difference between the 2.375 length and what it would be at the .625 intersection point. X=0.05468. so at that point the distance up to the centerline at 5 degrees and from the .625 intersection point would be 2.32032. Now we just need to find that normal to the 5 degree angle. COS(5)=y/2.32032. y=2.31149. So your distance is 2.31149. Another way to express this would be COS(5)*(2.375-TAN(5)*.625). Here's the dimension done in solidworks for clarity.trig.JPG Link to comment Share on other sites More sharing options...
[Me...] Posted January 2, 2020 Author Share Posted January 2, 2020 Please sign in to view this quote. It's funny you posted this just now because I was trying to model it and that's the EXACT same thing I got in SolidWorks... Capture.PNG Link to comment Share on other sites More sharing options...
[Ch...] Posted January 2, 2020 Share Posted January 2, 2020 good catch Link to comment Share on other sites More sharing options...
[An...] Posted January 3, 2020 Share Posted January 3, 2020 See attached.Contribution_03_01_2020.pdf Link to comment Share on other sites More sharing options...
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