Jump to content

Positional Tolerance


Recommended Posts

A obviously doesn't constrain all degrees of freedom in this case. If the z axis is perpendicular to -A-, then it controls [u,v,z]. The rest are left unconstrained. So then, the correct coordinate system for the DRF A in this case would be the one that conforms to A and gives the optimal results for the position 0.005 control on both holes. Normal position characteristics in Calypso will not optimize the unconstrained degrees of freedom--Calypso's best tool for a situation like this is a Best Fit of Bore Pattern.

(If there were only one hole with this FCF, it would essentially be a perpendicularity control.)
Link to comment
https://qualityforum.zeiss.com/topic/19676-positional-tolerance/#findComment-110714
Share on other sites

So, this is really interesting, where there are multiple holes and only a 'perpendicular' datum reference then the 32 TED centres are also included in the positional, but if only one hole is defined then it is perpendicular. I assume in this case also there is an implicit TED of 0 that wouldn’t come into effect so allows for rotational fitting.
Link to comment
https://qualityforum.zeiss.com/topic/19676-positional-tolerance/#findComment-110716
Share on other sites

So the only constraint you have is Datum Feature A. All -A- can do here is control perpendicularity of the two holes, BUT, the pattern must be held at the .005 tolerance simultaneously. What you have is two tolerance zones located exactly 32" apart and are perpendicular to Datum A. They can rotate and move around the part but are always 32" apart and always perp to A. Basically, they just bounce around inside the 0.025 tolerance zone to ABC. Its almost the same thing as a composite tolerance.
Link to comment
https://qualityforum.zeiss.com/topic/19676-positional-tolerance/#findComment-110718
Share on other sites

×
×
  • Create New...