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How Does Calypso Calculate Bilateral unequal dist. on profile


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Hey all..

We just recently started calling out profiles on our parts that have unequal bilateral distribution. I know on a regular profile, calypso takes the furthest point from nominal and multiplies it by 2 to get a profile value. My question is how does it do it on a unequal distribution? If I was a total of 0.016" with an U of 0.003", I'd obviously be out if I was on the inside any more then 0.0015". Any help would be appreciated.

Thanks,

Ryan
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From my understanding Calypso will find the center point of the tolerance zone and treat it like a standard bilateral from that point.
In your case .016 total with .003 inside, calypso would center the zone at .005 outside and you would get .008 maximum + or -.
So if you had a perfect part that measured 0.0 for the profile, the physical surface would be +.005 from the cad model surface.

For whatever reason i cannot attach the "ProfileCalls" calypso profile guide.......
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I'm with Roberto on this, except for one minor point. a U 0 0.003 would mean 0.003 outside the part, so the tolerance would be centered on -0.005.
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So would that mean if I ran the part and everything ran dead nuts on, would I have a value of 0.010"? I.E. since the tolerance is centered at -0.005" and I'm running at 0 (or the nominal of the part) that I would then be above the tolerance center zone? Appreciate the fast responses you all have. Thanks for the insight so far.
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Yes, at print nominal you would have a profile deviation of about .010

I also agree with Aaron, i think i got my inside & outside flipped
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