[To...] Posted December 12, 2024 Share Posted December 12, 2024 There is a profile to |D-E|A|. The drawing calls out 2 planes, one as datum D and the other as datum E. The plane on the bottom is datum A. Any suggestions for how to set up D-E as the Primary Datum? Is this a case of using a Geometry Best Fit alignment of D and E and using the alignment in the profile? I really don't care about datum A because it doesn't control any degrees of freedom. Link to comment Share on other sites More sharing options...
[Ma...] Posted December 12, 2024 Share Posted December 12, 2024 Wouldn't be D-E as symmetry? Link to comment Share on other sites More sharing options...
[Ch...] Posted December 13, 2024 Share Posted December 13, 2024 It depends to the software that are you are planning to use for this inspection task. For ZI the answer would be that you can use a wedge as a datum starting with ZI 2025. For Calypso I have no idea what a good solution would be. Link to comment Share on other sites More sharing options...
[Je...] Posted December 13, 2024 Share Posted December 13, 2024 (edited) Like Martin told, in Calypso a symmetrie of the (outer tangent) planes should work Edited December 13, 2024 Link to comment Share on other sites More sharing options...
[To...] Posted December 13, 2024 Author Share Posted December 13, 2024 Thank you for your feedback. I don't know if this matters but the 2 planes are not at an equal angle netting an A2 projection angle of 4.25° on the symmetry plane. This symmetry reduces the degrees of freedom from 5 to 4, which now means Datum A can control translation in Z. The considered feature is a plane (not shown) that is parallel to A. I don't know if the design intent/function is to locate/orient from D-E or A. Link to comment Share on other sites More sharing options...
[Je...] Posted December 13, 2024 Share Posted December 13, 2024 (edited) This is an interesting characteristic, Tom. I agree with Martin and the others that a symmetry of the two planes, in ASME speak a "midplane," is the primary datum. A literal interpretation of the print would be to have D-E constrain everything that it can, which I surmise is two degrees of rotation and one degree of translation. That allows Datum A to control one degree of rotation this is the planar rotation (clocking, skew, etc.), and also one degree of translation which is perpendicular to the axis of the surface of the D-E symmetry until its intersection of Datum A. The only remaining degree of freedom that is left unconstrained is translation mutually perpendicular to the axis of both Datum D-E and Datum A. Edited December 13, 2024 Link to comment Share on other sites More sharing options...
[To...] Posted December 13, 2024 Author Share Posted December 13, 2024 Please sign in to view this quote. My bad on the number of degrees of the midplane. Link to comment Share on other sites More sharing options...
[Ti...] Posted December 13, 2024 Share Posted December 13, 2024 (edited) The idea the planes are not equally angled from each other becomes flawed when they are the primary datum. Why? That is because it is a matter of perspective. I throw you into a dark room and give you a part with two planes a primary and a fixture with the same angled two planes. You put the part in the fixture and the midplane sets an X plane immediatly and eventually dertermins Z+. The only reason you could have to assume they are not equal to each other is by looking at other features on the part. But the other features are a slave to the primary datums. In the below image, the left would be thinking the two planes in the fixture are not a symmetrical angle to each other, but the right fixture the planes are symmetrical. I bring this up b/c this callout should remove 5 dof. it is identical to a tapered slotted hole/boss which is the only geometric shape that removes all 6 dof, except in this case there lacks the two opposing radii to stop the translation in the fixture. Here you toss the part below in a 105 deg v-block glued to a surface plate and the part can only be pushed to and from the operator. Z is set by the intersection line of the two planes. Similar to a vertex point of a cone primary datum, or again the line created with a tapered slotted hole. You could customize your datum frames to remove Z from the D-E and insert A if that be the case. Edited December 13, 2024 Link to comment Share on other sites More sharing options...
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