[Ji...] Posted January 13, 2025 Share Posted January 13, 2025 Hello all, Attached is my question. Who can help me find the best way? Thanks. Question Description.docx Link to comment Share on other sites More sharing options...
[Ma...] Posted January 13, 2025 Share Posted January 13, 2025 I don't think that for ISO there should be OT plane - it should be Gauss too. If you would evaluate perpendicularity on plane in diagonal direction, then it will report bigger number than evaluation in parallel direction. So i am not sure if TP here is reporting the biggest deviation from measured points or calculated plane shape. Try turning on CAD evaluation graphics to see where is the biggest deviation. It can help you understand that. Link to comment Share on other sites More sharing options...
[Pa...] Posted January 13, 2025 Share Posted January 13, 2025 Hello jinxi, Be sure the plane Datum A is outer tangential in your "KS01_A B C" alignment used in caliper distance. Link to comment Share on other sites More sharing options...
[Ji...] Posted January 14, 2025 Author Share Posted January 14, 2025 Please sign in to view this quote. Hello Pavel, we tried again... it still not meet the Position.... Link to comment Share on other sites More sharing options...
[Ji...] Posted January 14, 2025 Author Share Posted January 14, 2025 Please sign in to view this quote. Hello Martin, Can you give me any info from ISO standard? Customers think OT plane meets the requirement for ISO standard. Link to comment Share on other sites More sharing options...
[Je...] Posted January 14, 2025 Share Posted January 14, 2025 Please sign in to view this quote. Hello Jinxi, the costomers are right, for Position your feature must be LSQ (ISO 1101), and your datum must be outer tangential (ISO 5459). So, if you use caliper distance, your coordinate-system must be on that ot-datum, like you did. Looks right above. The biggest deviation from nominal (wich can be min or max) x2 must give you the same result like the position-result. Greets Jens Link to comment Share on other sites More sharing options...
[Ji...] Posted January 14, 2025 Author Share Posted January 14, 2025 Please sign in to view this quote. Hello Jens, the results for Caliper dis =(23.942-23.67)*2 = 0.544 position = 0.512 it's not same.... Link to comment Share on other sites More sharing options...
[Je...] Posted January 14, 2025 Share Posted January 14, 2025 what happens, when you use in position (not gdt-position) your coordinate-system as datum? Link to comment Share on other sites More sharing options...
[Ji...] Posted January 14, 2025 Author Share Posted January 14, 2025 Position is ok. but in GD&T position ,i can't found the method.... Link to comment Share on other sites More sharing options...
[Je...] Posted January 14, 2025 Share Posted January 14, 2025 (edited) in Extras->Settings->Measurement->Form Datum, wich Evaluation Method for Datum did you set? And wich Default in Extras->Settings->Measurement->Form & Location? Edited January 14, 2025 Link to comment Share on other sites More sharing options...
[Je...] Posted January 14, 2025 Share Posted January 14, 2025 (edited) and, in your coordinate-system, do you have both, rotation in space AND x origin set to outer tangent? Edited January 14, 2025 Link to comment Share on other sites More sharing options...
[Ji...] Posted January 14, 2025 Author Share Posted January 14, 2025 Please sign in to view this quote. yes. check the follow: Link to comment Share on other sites More sharing options...
[Je...] Posted January 15, 2025 Share Posted January 15, 2025 Please sign in to view this quote. Link to comment Share on other sites More sharing options...
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