Jump to content

Need help with a cone measurement


---
 Share

Recommended Posts

Hello everyone,

I need your help in order to measure the length of the side of the cone with the CMM. I received a new drawing from the customer and there is a 0.5mm length call out which is from the intersection of the through hole and a 90° angle to the intersection of the 120° angle and the 90° angle as you can see on the drawing. Thank you in advance

image.png.5b95be84516bd39fe2ab868f5549de2c.png

Link to comment
Share on other sites

There are a few ways to do this. One would be to probe three lines (One on each angled surface) and intersect them.

For example. Probe a 2d line on top of the left cylinder. Probe the second line up the short surface of the 60° surface.

Probe the third line up the 45° surface. Intersect the first line with second and the second with third. Create a local

alignment using the first intersection (XYZ origin) Use the second intersection as the planar rotation. Now do a point-to-point

distance referencing that local alignment.

  • Like! 1
Link to comment
Share on other sites

You can also create a cylinder and 2 cones on the 45° & 60° surface. pull the cylinder and 45° cone into an intersection & make sure the "shell" checkbox is selected on for both. Do the same with the 45° cone and the 60° cone.

You will now have 2 circles that you can grab a distance with.

  • Like! 1
Link to comment
Share on other sites

Thank you Clarke for your assistance. I created the lines and the intersection points. For measuring the length I used the polar distance using the 45° angle as my primary datum.  I do not have parts to measure yet but it seems that it will work.

Thanks again

 

image.png.d626af0df130435d89dc441eb9c7c973.png

  • Like! 1
Link to comment
Share on other sites

Please sign in to view this quote.

Hello Ryan and thank you for taking the time to review and replay to my question. I have created the intersections but I am not sure how I can check the distance which is oriented at an angle. Could you please help me on this?

Thanks

 

 

Link to comment
Share on other sites

 Share

×
×
  • Create New...