[Ma...] Posted June 8, 2025 Share Posted June 8, 2025 I need to convert I,j,k vectors into decimal degree angular values for a project I’m working on. Any help would be appreciated. Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Share Posted June 9, 2025 Inside Calypso? -> You can chage display All angles or one combined angle? Link to comment Share on other sites More sharing options...
[Cl...] Posted June 9, 2025 Share Posted June 9, 2025 If you have the XYZ nominals I have a spreadsheet that will calculate the IJK vectors for them. Will that help? 1 Link to comment Share on other sites More sharing options...
[Cl...] Posted June 9, 2025 Share Posted June 9, 2025 (edited) ARC VECTOR CALCULATION'S.xls I downloaded this from the forum years ago. Edited June 9, 2025 Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Author Share Posted June 9, 2025 (edited) Please sign in to view this quote. Thanks Clarke But what I'm looking for is the formula to take a i,j,k vector and convert it to an angle value. I think I have to convert it to a Euler Angle then maybe I'll have that angle, but my tests are not working. Edited June 9, 2025 Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Author Share Posted June 9, 2025 Please sign in to view this quote. Not specific to Calypso. I'm working on another project. Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Share Posted June 9, 2025 (edited) Please sign in to view this quote. So you want one combined angle? I think ijk are from 0 to 1 and it should be calculated with sin,cos and tan mainly - there should be formula on google. So what? you want to convert each ijk to angle or that combinated one? To find the angles associated with a vector given in IJK notation (I, J, K), you need to calculate the direction cosines and then use the inverse cosine function (arccos). The direction cosines are found by dividing the components of the vector by its magnitude. Here's a breakdown: 1. Calculate the Magnitude of the Vector: The magnitude of a vector (I, J, K) is calculated as: sqrt(I^2 + J^2 + K^2). 2. Calculate the Direction Cosines: The direction cosine for the x-axis (angle with the x-axis) is: I / magnitude. The direction cosine for the y-axis (angle with the y-axis) is: J / magnitude. The direction cosine for the z-axis (angle with the z-axis) is: K / magnitude. 3. Calculate the Angles: To find the angle associated with each axis, use the arccos function: Angle with x-axis = arccos(I / magnitude). Angle with y-axis = arccos(J / magnitude). Angle with z-axis = arccos(K / magnitude). Edited June 9, 2025 1 Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Author Share Posted June 9, 2025 Thank you Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Author Share Posted June 9, 2025 I would like to convert each one Link to comment Share on other sites More sharing options...
[Ma...] Posted June 9, 2025 Share Posted June 9, 2025 So just use arc cos with i,j,k values - magnitude here is always 1 so that's it https://nexus.hexagon.com/community/public/pc-dmis/f/pc-dmis-for-cmms/114263/ijk-angle-conversion Link to comment Share on other sites More sharing options...
[Ri...] Posted June 9, 2025 Share Posted June 9, 2025 Can't recall who created this file. Direction Vector Calculator.xls 2 Link to comment Share on other sites More sharing options...
[na...] Posted June 10, 2025 Share Posted June 10, 2025 (edited) Please sign in to view this quote. I've used this web calc in the past -> https://www.mathsisfun.com/algebra/vector-calculator.html Edited June 10, 2025 2 Link to comment Share on other sites More sharing options...
[Tr...] Posted June 11, 2025 Share Posted June 11, 2025 THANKS! I had forgotten how much I needed/wanted these! Link to comment Share on other sites More sharing options...
[Je...] Posted June 18, 2025 Share Posted June 18, 2025 Please sign in to view this quote. Please sign in to view this username. Your link opened a portal to an upside down nether region filled with demons. 3 Link to comment Share on other sites More sharing options...
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