Radial Distance

[[ni...]]

Hi guys,

not a big deal, but I don't anderstand what Radial distance (R) is ?

in refentiel2 the radial distance is exactly equal to the distance along Y axis, but in base alignement not at all, but the two refentials have the same Y axis ! , (ref2 is a rotation of base alignement along Y axis.)

and a secondary question, I have to use "space point" to have the good distance, with "contact point" the value are weird. What for "contact point"  are ?

 

thanks

Nico

[[Ma...]]

Hi,

what i found is that R measurement is calculated from axis of Rotation in space ( primary ). So with R you won't see difference in heights, while 3D will calculate distance in all three axis.

If you don't need this fancy stuff with MIN/MAX and meas. point/ feature then you can use polar distance - it will use feature's alignment.

About space point - look into manual about calculating space/plane and other points. I am using plane points mostly - not sure why you need space points.

[[ni...]]

Hi Martin,

 

you are right, plan point and space point give same results. contact points seems to correct the vector by the axes and in this case I am at 45° calyspo return  doomy results.

when I defin a point it is by default in "contact point" is it a way to define plan point by default ?

the work is done, I have my result with 3 method, : distance along axis in a rotationned referentiel, polar distance and texte result with :getActual("Point5").coordPolRadius- getActual("Point4").coordPolRadius, for the last "reference for coordinate cylindrical" in the element windows has to be set to Y

still don't figure how "R" work. I have effectively the distance by the primary in the first case (referentiel2) , but not with base referentiel, wich have the same primary ! 

 

 

[[Ma...]]

You can define default evaluation for a point, but only from features menu. Using mouse to take points on model will select space point.

"R" work like this - it will project measured points on primary plane, calculate difference in X and Y ( or any relevant axis ) and use trigonometry to obtain the longest line of triangle - Pythagoras - R = √(delta_x² + delta_y²)

https://www.calculator.net/pythagorean-theorem-calculator.html

[[ni...]]

so I have I  have to modify point by point I can't modify all in one click ? wich is the gain as long space point give the same result than plan point ?

 

I will keep an eye open, cause in my case I can't figure the calcul of R, maybe latter with an other case I will understand :) 

 

thanks

 

[[Ma...]]

I think you can modify this via editor for features in Prepare menu

[[Ma...]]

R is basically the hypotenuse of the triangle based on the alignment. This is projected on the working plane and is not the 3d measurement.

[[ni...]]

Finaly I got it, R equal to length of projection in Z/X (or in Z/Y if length (projection ZY) smaller than  length (projection ZX)