[Cl...] Posted August 19 Share Posted August 19 (edited) The part is an OD cylinder 0.1760 Ø (R.088, long leg of the triangle). It has a laser etched line parallel and on the same axis to a plane (AO connector if you are familiar with that) The etched line must be within ± 2° to center of the plane. I did the math and got 0.003 (short leg), but because it's a round surface I'm not sure the short leg of the triangle isn't slightly different than 0.003? Edited August 19 Link to comment Share on other sites More sharing options...
[Cl...] Posted August 19 Author Share Posted August 19 Addendum. Imagine looking at a pie, sliced in 2° segments. I need to know the width of the fat end of one slice. Link to comment Share on other sites More sharing options...
[Ma...] Posted August 19 Share Posted August 19 I think you need to find the chord length based on the radial distance Chord Length Formula There are two basic formulas to find the length of the chord of a circle which are: Formula to Calculate Length of a Chord Chord Length Using Perpendicular Distance from the Center Chord Length = 2 × √(r2 − d2) Chord Length Using Trigonometry Chord Length = 2 × r × sin(c/2) Where, r is the radius of the circle c is the angle subtended at the center by the chord d is the perpendicular distance from the chord to the circle center Example Question Using Chord Length Formula Question: Find the length of the chord of a circle where the radius is 7 cm and perpendicular distance from the chord to the center is 4 cm. Solution: Given radius, r = 7 cm and distance, d = 4 cm Chord length = 2√(r2−d2) ⇒ Chord length = 2√(72−42) ⇒ Chord length = 2√(49−16) ⇒ Chord length = 2√33 ⇒ Chord length = 2×5.744 Or , chord length = 11.48 cm Link to comment Share on other sites More sharing options...
[Ri...] Posted August 19 Share Posted August 19 The arc length is just the radius multiplied by the angle (in radians). https://www.ajdesigner.com/phpcircle/circle_arc_length_s.php You can also derive this using Curve - Curve Length. Link to comment Share on other sites More sharing options...
[Cl...] Posted August 19 Author Share Posted August 19 Thanks Richard. I forgot all about curve length! 1 Link to comment Share on other sites More sharing options...
[Cl...] Posted August 20 Author Share Posted August 20 Ok. It turns out that 2° is 0.00307". Which I doubled to use as a bi-lateral true position of 0.00614. I need the position deviation converted to degrees. I have the calculator that you sent me, but I need a formula to enter into a result Element. Any help is greatly appreciated. Link to comment Share on other sites More sharing options...
[Ha...] Posted August 20 Share Posted August 20 Please sign in to view this quote. If I'm reading the thread correctly, the formula for converting the position deviation to an angle in degrees would look something like this: angle in degrees = (position deviation / radius) * (180 degrees / PI radians) 1 Link to comment Share on other sites More sharing options...
[Cl...] Posted August 20 Author Share Posted August 20 Yes, thank you! Link to comment Share on other sites More sharing options...
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