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Angle calculation


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The part is an OD cylinder 0.1760 Ø (R.088, long leg of the triangle). It has a laser etched line parallel and on the same axis to a plane (AO connector if you are familiar with that)

The etched line must be within ± 2° to center of the plane. I did the math and got 0.003 (short leg), but because it's a round surface I'm not sure the short leg of

the triangle isn't slightly different than 0.003?

Edited
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I think you need to find the chord length based on the radial distance
 

Chord Length Formula

There are two basic formulas to find the length of the chord of a circle which are:

Formula to Calculate Length of a Chord
Chord Length Using Perpendicular Distance from the Center Chord Length = 2 × √(r2 − d2)
Chord Length Using Trigonometry Chord Length = 2 × r × sin(c/2)
 

Chord Length of a Circle Formula

Where,

  • r is the radius of the circle
  • c is the angle subtended at the center by the chord
  • d is the perpendicular distance from the chord to the circle center

Example Question Using Chord Length Formula

Question: Find the length of the chord of a circle where the radius is 7 cm and perpendicular distance from the chord to the center is 4 cm.

Solution:

Given radius, r = 7 cm

and distance, d = 4 cm

Chord length = 2√(r2−d2)

⇒ Chord length = 2√(72−42)

⇒ Chord length = 2√(49−16)

⇒ Chord length = 2√33

⇒ Chord length = 2×5.744

Or , chord length = 11.48 cm

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Ok. It turns out that 2° is 0.00307". Which I doubled to use as a bi-lateral true position of 0.00614.

I need the position deviation converted to degrees. I have the calculator that you sent me, but I need

a formula to enter into a result Element. Any help is greatly appreciated.

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