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Zero tolerance in coaxiality


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Hello colleagues,

I have a drawing with zero tolerance for coaxiality but a maximum material condition.
How should this drawing be interpreted and how can it be implemented in CALYSO?

And again and again the question of whether it is coaxiality or concentricity...

Best Regards
Karsten

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When you're working with ASME, it depends: in the newest standard, there is no more concentricity. The symbol has been eradicated altogether and has been substituted with the position symbol.

So this could be an older ASME standard, but there is no Maximum Material Condition for concentricity AFAIK, so here, you're obviously working in ISO (it's "2x" in ISO, and "2X" in ASME). In ISO, it's always coaxiality, and in this case it's the coaxiality of the Maximum Material Boundary of the common axis Ø10.65. The diameter of the Maximum Material Boundary is Ø10.65 +0.05 = 10.70 mm, and that means the minimum circumscribed cylinder (over all segments) must not violate the Maximum Material Boundary at the nominal position of datum A-A|B.

For the manufacturing process it means, that the diameter should be made preferably at the lower end of the tolerance. If your Ø10.65 is made 10.60 at perfect form, your coaxiality tolerance will be 0.01.

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You will form a cylinder from two circles with a diameter of Ø10.65. (The coaxiality tolerance will come from the maximum material condition.)

Because it is Cz, you must obtain a cylinder from this. Since it will be a cylinder measurement, this must be coaxiality.

If you keep the diameter tolerance at a minimum level, the tolerance it will give you will be larger.

 

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Hi Daniel, Hi Ünal,

Thank you so much! 

We very rarely require maximum material conditions. And yes, it is ISO.
We still use CALYPSO 7.4.24, so the evaluation according to the centre line must be used for cylinders in order to be ISO-compliant. The default is ASME, for whatever reason... 🙂

Thank you very much for your efforts!

Only a example to show ISO versus ASME...
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