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Problem with constructing diameter form sphere intersection.


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Do you mean you need to find the plane where the intersection is ⌀17.5 or you need to find the diameter of the intersection of the sphere and a plane 5.80409 from its center point? Either can be found using a Result Element and some basic trig.

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This is my method too, can't remember where or when I learned it, may have been you.
No math involved when using this method.
If the circle diameter is on some tilted axis, create an alignment then the cylinder to that alignment.

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I not either. But it makes sence since this with TED radius/diameter will tell you exact position on a sphere ( made from geometry of course ).

We had similar problem on a part, where you had center from a circle and rotation was stopped by a point on a further side ( like a pin )
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