[An...] Posted February 6 Share Posted February 6 I'm trying to create a theoretical circle inside a triangular-shaped machined pocket in order to give an X/Y position for the pocket. The pocket is dimensioned with a profile tolerance, but that doesn't help the machine operator make adjustments, hence the want for X/Y position. I'm taking several points on the wall of the pocket for the profile (then calculating manually) as we don't have Curve. I then recalled these points into three 3D lines, then recalled the lines into a circle with Max Inscribed Element selected under evaluation. This doesn't work though and gives me this result: I've tried creating 3 lines (not recalling points), then creating the circle from those and get similar results. I've also tried just selecting the points that I used to make the 3D lines. What am I doing wrong? For reference, the pocket is only .035" deep with a nominal circle size of .408". Thanks, Andrew Link to comment Share on other sites More sharing options...
[Ma...] Posted February 7 Share Posted February 7 What would recalling your lines into a point do? Link to comment Share on other sites More sharing options...
[Ch...] Posted February 7 Share Posted February 7 I think there are easier ways to get the location of this triangle. However, I have an idea boiling it down to points, its pretty length, if you don't have any luck, let me know I'll try to explain. Link to comment Share on other sites More sharing options...
[Ma...] Posted February 7 Share Posted February 7 Recall measured points into circle and check inscribed circle Link to comment Share on other sites More sharing options...
[Ma...] Posted February 7 Share Posted February 7 Another method ( based on your CAD model - shorter line is not over center ) : Make symmetry from line 1 and 2 Make symmetry from line 1 and 3 Intersection them to get center point Link to comment Share on other sites More sharing options...
[Da...] Posted February 7 Share Posted February 7 Please sign in to view this quote. That will only work if there are measured points at the tangent points. Otherwise it will fail. But your second idea about the symmetry lines was good. Link to comment Share on other sites More sharing options...
[Ja...] Posted February 7 Share Posted February 7 How are you checking the profile? The graphics of the profile do not help? Link to comment Share on other sites More sharing options...
[Da...] Posted February 7 Share Posted February 7 Please sign in to view this quote. Now construct a perpendicular from center point to 1 original line and double the value. 😉 Link to comment Share on other sites More sharing options...
[Ma...] Posted February 7 Share Posted February 7 Please sign in to view this quote. I think author didn't ask for diameter/radius - only origin. Link to comment Share on other sites More sharing options...
[An...] Posted February 9 Author Share Posted February 9 Please sign in to view this quote. I tried this and it does not work. The circle is not fit to the pocket. Please sign in to view this quote. This works, but is a bit messy/complicated. I guess it will have to do though. Please sign in to view this quote. We aren't actually using the Profile characteristic because you can only use it with a curve (which we don't have) or circle/arc. We use a Result Element and calculate the profile based on the min and max points. This means no graphic display sadly. Link to comment Share on other sites More sharing options...
[Ma...] Posted February 9 Share Posted February 9 Please sign in to view this quote. Well one last thought. Since you don't have a curve opt i wonder how it would work with similar steps. make geometry alignment use all three lines allow translation and rotation. make theoretical point with nominal in center of a pocket set point's alignment as previously geometry alignment. recall element into base alignment This will give you that origin with bestfit ( our it should be possible to report that origin with Result element ) Link to comment Share on other sites More sharing options...
[Cl...] Posted February 12 Share Posted February 12 If you know the theoretical size of the circle you can measure the two planes opposite one another, offset them by the circle radius and intersect. That should give you the center. Link to comment Share on other sites More sharing options...
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