[Za...] Posted January 4, 2023 Share Posted January 4, 2023 Hello all, I'm pretty sure what I'm asking isn't that difficult, but I've never had to mess with polar coordinates in Calypso before, so this is all new to me. I'm looking to get the polar dimensions of the three highlighted features. Can anybody assist? Thanks, Zach Link to comment Share on other sites More sharing options...
[Za...] Posted January 4, 2023 Author Share Posted January 4, 2023 Let's say my part is setup where the origin is at the middle circle Link to comment Share on other sites More sharing options...
[Ma...] Posted January 4, 2023 Share Posted January 4, 2023 Create characteristic for each circle with: Size - Distance - Polar 2d Link to comment Share on other sites More sharing options...
[Ch...] Posted January 4, 2023 Share Posted January 4, 2023 I would recommend the normal position callout and just switching it to Polar. If you want to report all at once then switch it to bore pattern position and then select polar; HOWEVER, my polar stuff hasn't been working for me for a couple of versions now. Since I don't use it much it is not an issue, just annoying. Is anyone else having trouble reporting positions in polar coordinates, or is it just me? Link to comment Share on other sites More sharing options...
[Ch...] Posted January 4, 2023 Share Posted January 4, 2023 I think it depends on the feature's represnetation. Try this, highligh the feature(s)m then click on this button on the tool bar and change to modify>Cylindrical ... Verify the feature itself is then in polar ... Then try your position again. Good luck. Link to comment Share on other sites More sharing options...
[Za...] Posted January 4, 2023 Author Share Posted January 4, 2023 Awesome stuff, I have a few things to finish up and then I'm going to look at this again and try to get it going. Link to comment Share on other sites More sharing options...
[Gu...] Posted January 16, 2023 Share Posted January 16, 2023 Make each circle's perpendicular to the center of the axis. (check same height) Then use 2 of the 3 perpendiculars to create the angle between elements ==> 120 degrees Link to comment Share on other sites More sharing options...
[Za...] Posted February 9, 2023 Author Share Posted February 9, 2023 Please sign in to view this quote. This is how I was obtaining the angles originally, but I was told it needs to be in polar coordinate form 🙄 Link to comment Share on other sites More sharing options...
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