[To...] Posted February 15, 2019 Share Posted February 15, 2019 I'd like to hear how you guys measure a datum target that has a .250 diameter specified. I've always believed that this would represent the diameter of a pin used on a fixture located at the BASIC dimension. To reproduce this methodology, I suppose a strategy that scans the entire .250 diameter surface would be required. There is the ability to create this scanned path in the point's strategy window but it appears only a LSQ evaluation is possible and thus would not mimic how a solid pin might detect the surface. Would it be "close enough"? 🤣 Your thoughts? Link to comment Share on other sites More sharing options...
[Me...] Posted February 15, 2019 Share Posted February 15, 2019 Are you able to measure a plane with a circle and adjust the circle size & location and change it to outer tangential? Link to comment Share on other sites More sharing options...
[He...] Posted February 16, 2019 Share Posted February 16, 2019 In the release info for 6.6 they mentioned that it is possible to use outer tangential feature for points. I'm still at 6.4 so i haven't tried it myself yet. Link to comment Share on other sites More sharing options...
[Aa...] Posted February 18, 2019 Share Posted February 18, 2019 I would set the datums up as planes, but only measure them in the zones marked as datum targets. (If the surface geometry is weird, you might have to use offset plane, or something like that.) If C is tertiary (I know, strange guess...), I would constrain it's orientation to the primary and secondary. Link to comment Share on other sites More sharing options...
[To...] Posted February 18, 2019 Author Share Posted February 18, 2019 FYI, there are 6 datum targets, 3 for A, 2 for B and 1 for C. Henrik, you are correct. 2018 (v6.6) allows LSQ Outer Tangential and Inner Tangential. Link to comment Share on other sites More sharing options...
[Aa...] Posted February 18, 2019 Share Posted February 18, 2019 Please sign in to view this quote. Right, so I A is primary, B is secondary, and C is tertiary (who would've guessed it...) I would make all three planes. B should have its orientation constrained to A, and C should have its orientation constrained to A and B. Outer Tangential on each. Link to comment Share on other sites More sharing options...
[An...] Posted February 19, 2019 Share Posted February 19, 2019 See attached.Contribution_19_02_2019.pdf Link to comment Share on other sites More sharing options...
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