I need to measure a circular groove

[[Ca...]]

I need to measure a circular groove.
I need to determine the groove width and center circle diameter.
What's the best way to determine the center circle diameter from the inner and outer diameters?
The groove is for a seal.
Is there such a thing as a circle of symmetry?

[[Cl...]]

Sounds like an oval? If you have a model you should be able to extract a nominal circle segment from it.

Open that circle feature. Copy/paste the extracted segment. Set it 180° from the first. Add points.

Highlight both segments, tick "Group Circle Paths". Probe single points and constrain work-plane coordinates.

With curve, scan around the entire surface.  Recall the points into a nominal circle and set the evaluation to Maximum Inscribed Element"

[[Ma...]]

That groove is like torus or cylinder?

[[Ma...]]

Is the groove on a flat face, like for a face sealing O-ring? 

If so, you should be able to measure the inside and outside diameters of the groove and calculate the mean of the two diameters. You could probably also achieve a good representation of your "circle of symmetry" by recalling all of the feature points for both circles into a single circle with LSQ evaluation. Form deviation will be high, obviously, but the location and diameter output should be correct.

[[Lu...]]

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Would you need to make sure that both circles have the same amount of points in order to make sure the middle circle doesn't lean to the inner/outer circle? Or would that not matter

[[Ca...]]

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Like a cylinder, but only 0.2mm deep. So I only measure the top edge with the camera. This results in two circles. One for the inner diameter and one for the outer diameter.

[[Cl...]]

Is this similar to what you have?

[[To...]]

Use Result Element with a formula to subtract the radius of the smaller circle from the radius of the larger circle.

[[Ca...]]

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Well, I had that idea too. However, I was hoping Calypso would provide a ready-made function for that.

[[Ma...]]

Wouldn't caliper distance do that? setting with min-min or min-max - i am not sure, but this should work.

And inverting that ( min-max / max-min ) should report max and min distance.

Otherwise should work intersections, right? Or am I missing something?

Edited May 1, 2025

[[Ca...]]

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Für den Nutabstand ist der Messschieber Abstand ok. Aber die Mitte Nut ist damit nicht zu ermitteln. Dann bleibe ich dabei die beiden Kreise zu subtrahieren 

[[Ma...]]

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For that you can use mid or symmetry from circles. Nothing else is comming to my mind.