[Ma...] Posted Thursday at 01:23 PM Share Posted Thursday at 01:23 PM I am trying to figure out what my nominals would be if C was dimension back to A and B and B to A and C? I would think since B1 and B2 control rotation, you would only have one value in my case the Z distance from that B Datum the dimensioning Datum B to A and C...not sure. How would I set this up? Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 01:55 PM Share Posted Thursday at 01:55 PM I think - datum B is stopping rotation and also gives you origin in one axis. Unless you have RPS table telling you dimensions. Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 02:00 PM Author Share Posted Thursday at 02:00 PM (edited) So in this case I would be right in I would get a one directional Position, Since my origin is B and C intersect I would only get one value and the other would be zero as there is no deviation in one direction, the Origin is C, am I understanding what you're saying? The RPS is not dimensioned to the datums. Edited Thursday at 02:02 PM Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 02:43 PM Share Posted Thursday at 02:43 PM There is no base dimension from C to B, but CAD model will provide that. I assume for TP callout from datum A|C will be C your origin ( intersected with A ) Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 03:06 PM Author Share Posted Thursday at 03:06 PM Yes for the call-out for Datum B to A/C yes, that one is pretty straightforward as far as pulling the nominal dimensions from C to B1 and B2, not sure how rotation is controlled but I get the idea two planes 90° (A and C) intersecting, so I got the X and Z nominals off of the Cad, but the C to AB is still a little odd, I would assume the same notion two 90° planes intersecting at A Plane and B Line but where is the origin in that? This is what I got but I question if its correct. Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 03:31 PM Share Posted Thursday at 03:31 PM Those datums B and C - are they circles or how is looking their shape? If datum B is only symmetry of planes in Z, then you can not do TP for C and same for TP for B Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 03:43 PM Author Share Posted Thursday at 03:43 PM They are symmetry points and then a 3D line as they are a unique shape, can't really get a circle or cylinder off of them. Datum B1 and B2 are called back to A and C and Datum C is called back to AB, so I was thinking A and B intersect but you only get one direction as there is nothing controlling translation, for B back to AC, the origin is the intersecting planes of A and C but nothing really controlling rotation, I am using lines and points but as it was designed I am picturing the features as orthogonal planes. Does that make sense? Like in this example. I am not sure how else to set this call-out up and welcome any suggestions. Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 04:22 PM Share Posted Thursday at 04:22 PM For me is not making sense any of those TP. For C you would need to have only in X direction, which can not be given by datum B and for B's - they need controling in Z, but C is giving X. I would ask customer/engineer how they ment this to be measured. Link to comment Share on other sites More sharing options...
[Ma...] Posted Thursday at 10:25 PM Author Share Posted Thursday at 10:25 PM If they were measured as circles...I realize they are not but center is center. Link to comment Share on other sites More sharing options...
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