[Fe...] Posted July 29 Share Posted July 29 Good morning, how can I calculate the 10 degrees as shown in detail Y? Thank you. Link to comment Share on other sites More sharing options...
[Ma...] Posted July 29 Share Posted July 29 You can either scan it like a cone or like a line. For cone you then report half of it's angle. For line you then report angle between features ( old Calypso has that close to profile callouts ) 1 Link to comment Share on other sites More sharing options...
[Jo...] Posted July 29 Share Posted July 29 Looks like the angle is relativ to the the extremly short area (1,924). That is in general not a good idea because minor deviations (form) on that short area will result in big deviations in the angle. Theoretically the angle should be the same as to the area "11,14". But you sould have of course detailled knowledge about the usage/installation to just replace the the one reference of the angle. I would measure both and compare to get a feeling for the situation. Link to comment Share on other sites More sharing options...
[Fe...] Posted July 29 Author Share Posted July 29 So can I scan the 99.5 circle and any circle of the cone and insert it into the cone half-angle feature? Link to comment Share on other sites More sharing options...
[Ma...] Posted July 29 Share Posted July 29 For a cone you need at least two circular paths or helix to obtain it's angle. That 10° is meant from axis - not that little area. 1 Link to comment Share on other sites More sharing options...
[Jo...] Posted July 29 Share Posted July 29 Please sign in to view this username. How do you tell by the information given? The line is clearly on the the "little area". Because it would make sense or any hard tell? Link to comment Share on other sites More sharing options...
[Ma...] Posted July 29 Share Posted July 29 Please sign in to view this username. There is a runout callout to A, then i assume that 10° is half of that cone or angle of line to A axis. I can not tell more since i don't see if it's full circle/cone or just a half. Link to comment Share on other sites More sharing options...
[Jo...] Posted July 29 Share Posted July 29 I share your assumption. The drawing is kind of bad in that regard. They could have drawn the angel to the axis. 2 Link to comment Share on other sites More sharing options...
[Fe...] Posted July 29 Author Share Posted July 29 Link to comment Share on other sites More sharing options...
[Fe...] Posted July 29 Author Share Posted July 29 So they can be more understanding Link to comment Share on other sites More sharing options...
[Ch...] Posted July 29 Share Posted July 29 Ciao Frederico, It would be best if you measured a cone with several lanes, then you have the cone angle. Link to comment Share on other sites More sharing options...
[Fe...] Posted July 30 Author Share Posted July 30 I need to calculate the angle between the Ø99.5 circle and the cone Link to comment Share on other sites More sharing options...
[Ma...] Posted July 30 Share Posted July 30 (edited) That circle is too short to obtain plausible result. Edited July 30 Link to comment Share on other sites More sharing options...
[Ri...] Posted July 31 Share Posted July 31 From what I see you have about 34.576 of length to scan; I don't see the angle as only in the 1.924 reference dim. I cone with 3 or 4 circular scans should be sufficient. Link to comment Share on other sites More sharing options...
[Ma...] Posted August 1 Share Posted August 1 Please sign in to view this quote. You cannot, pratically. Circle surface scanning is too litle. You have to start form a solid calypso allignment starting from Datum A, then scan the cone on two far section, then on charatheristic choose "semi angolo del cono". Link to comment Share on other sites More sharing options...
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