[St...] Posted yesterday at 09:03 AM Share Posted yesterday at 09:03 AM Ich benötige Hilfe bei der Umsetzung einer Lagen- bzw. Schnittpunktmessung an einer schrägen Fläche. Das Breitenmaß von 3,8 mm muss dabei fest definiert sein. Anschließend möchte ich ermitteln, an welcher Längenposition sich dieses Maß befindet. Link to comment Share on other sites More sharing options...
[Ma...] Posted yesterday at 09:09 AM Share Posted yesterday at 09:09 AM Is it diameter or box? You can make theoretical plane or cylinder and make intersection - use 3.8 as nominal and you will get correct reading for 9.6 Link to comment Share on other sites More sharing options...
[St...] Posted yesterday at 09:14 AM Author Share Posted yesterday at 09:14 AM It is a cylinder with a sloped surface on one side. I tried to create a theoretical plane, but I think I’m doing something wrong and could use some help. Link to comment Share on other sites More sharing options...
[Ma...] Posted yesterday at 09:19 AM Share Posted yesterday at 09:19 AM So 4° is a plane? Then make theoretical plane at center and perpendicular to 4° plane - their intersection will create a line. Then make another theoretical plane at half of 3.8 and make another intersection with this line to get a point. Link to comment Share on other sites More sharing options...
[Ch...] Posted yesterday at 10:17 AM Share Posted yesterday at 10:17 AM Moin Stefan, kannst Du einen Kegelmessen an der stelle? Wen ja mit dem Element Kegelzusatz, findest Du unter "Verknüpfen" Link to comment Share on other sites More sharing options...
[St...] Posted 6 hours ago Author Share Posted 6 hours ago Moin Christian, so einfach ist es leider nicht. Auf der Zeichnung ist es etwas schwer zu erkennen, aber es ist kein Kegel, sondern eine einseitige schräge Fläche. Ich muss eigentlich herausfinden, an welcher Stelle das Teil genau 3,8 mm breit ist. Aus dieser Stelle soll dann das Längenmaß 9,6 ± 0,3 mm resultieren. Link to comment Share on other sites More sharing options...
[Ma...] Posted 6 hours ago Share Posted 6 hours ago I would start from bottom of that bigger cylinder. make alignment from right cylinder, rotation stopped by 4° plane ( origin from cylinder ) make intersection of theo plane to obtain bottom line make theo line or plane at distance 3,8 from line in step 2 make intersection of step 3 and 4° plane Different approach can lead to some differences in result of distance 9,6. Problematic is direction of this dimension. 4°. For every 0,01mm difference in [3,8] will lead into 0,143mm for 9,6 dimension. Link to comment Share on other sites More sharing options...
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