[Fe...] Posted yesterday at 02:33 PM Share Posted yesterday at 02:33 PM Good evening, how can I calculate this angle? I created a theoretical plane by placing it at the intersection, but it gives me a result of 60° Any help is appreciated, thank you Link to comment Share on other sites More sharing options...
[Jo...] Posted yesterday at 02:45 PM Share Posted yesterday at 02:45 PM (edited) Check the complementary angle (20)°, to see if there is something wrong with your theoretical plane or if the angle is 60°. Edited yesterday at 02:45 PM Link to comment Share on other sites More sharing options...
[Ma...] Posted 23 hours ago Share Posted 23 hours ago It's turned part, so i would scan just lines in part axis ( as viewed ) For small lines i usually do points instead of scan. If curve is available, then you can scan curve - make alignment from bestfit of curve to have correct data for small lines. Link to comment Share on other sites More sharing options...
[Fe...] Posted 3 hours ago Author Share Posted 3 hours ago Please sign in to view this username. In other words, the other angle? Link to comment Share on other sites More sharing options...
[Fe...] Posted 3 hours ago Author Share Posted 3 hours ago Please sign in to view this username. Unfortunately, I don't have the curves pack Link to comment Share on other sites More sharing options...
[Jo...] Posted 3 hours ago Share Posted 3 hours ago check this angle, so you see if 60° could be right. Link to comment Share on other sites More sharing options...
[Fe...] Posted 2 hours ago Author Share Posted 2 hours ago OK thanks, as soon as I have the part I will check it Link to comment Share on other sites More sharing options...
[Fe...] Posted 56 minutes ago Author Share Posted 56 minutes ago It returns a result of a 30° angle, so it is not correct Link to comment Share on other sites More sharing options...
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