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Perpendicularity to two datums


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Datum M is perpendicular to Datum C
Datum M is perpendicular to Datum A-B
I don't see why it can't.
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Here's another thread on the topic: viewtopic.php?t=10632&hilit=perpendicularity+two+datums

The tolerance zone will be perfectly perpendicular to the actual feature C. If its then perfectly perpendicular to the actual feature A-B it will no longer be perfectly perpendicular to the actual feature C, unless your part is perfect. But in this instance the tolerance zone could be perpendicular to C and parallel to A-B.
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I assume it's trying to control the Perpendicularity from A-B in the X-Y Plane. I tried Parallel Cylinder but that didn't work.

What about if you measured Circles at the Top and Bottom of each Cylinder and then Recalled the Center-Points into a Plane? It seems to work in principle in Simulation.

Thoughts?
659_d268ccfe5e26c9b173448be6f23143f9.zip
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I think that lines should not work in this cas, but planes should.

Create 3d line from recalled cylinders/circles to obtain angle. Then use formulas for new theoretical plane, where you use angle in same axis to get that parallel with 3d line.
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Erik has hit the nail on the head. This falls on Can-May-Must rule. Since the primary datum controls all DOF that the secondary would (and then 1 additional), the secondary datums controls are ignored. Once the "check box" is ticked in order of priority, they are no longer relevant from datums further down the list.

In order to evaluate -M- to Datum -C- and the -A-B- line (3d line btw; 2d = measured, 3d = constructed) they would need to be separate characteristics. If a print shows this tolerance in a single perpendicularity requirement, I would send this back to the designer for review.
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